benlehman: (Default)
benlehman ([personal profile] benlehman) wrote2006-06-05 06:05 pm

A math thought

The "four color map" problem is unique to two dimensional space. Why?

I was thinking about this years ago, and I forgot it until today.

Edit: Huh. Does it apply in four dimensions or not? I thought I answered that but I didn't actually. My hunch is that for three and higher dimensions the number of mutually adjacent objects is infinite.

Let's look at this:
dimensionality -> maximum mutually adjacent objects
0 -> 1
1 -> 2
2 -> 4
3 -> infinite
4 -> ?

Second Edit: It doesn't seem to matter if the space is open (infinite in all directions) or closed (loops at the edges.) Does it?

Third Edit: So the 1d case is trivial, largely because a 1d object can only be adjacent to two other objects, which clearly limits mutual adjacency. A 2d object can be adjacent to an infinite number of other objects, a fact which I make use of in my infinite mutually adjacent 3d objects construction (see comments). Perhaps mutual adjacency in dimension n depends on adjacency of the dimension n-1? That seems tempting, especially if we're going to view dimension n as dimenion n-1 with a time axis.

[identity profile] clockwise.livejournal.com 2006-06-05 07:17 pm (UTC)(link)
It took some thought, but you can force 5 colors within the tube.

The basic two dimensional 4 color scenario looks something like this:


          |      3
          |
          +---+
        1 | 2 +-----
          +---+
          |
          |      4


Within the unbound plane there is no region that you can add that touches all 4 of these regions without breaking one of the existing borders. Color 2 is thus free to be used elsewhere within the cube and you can not connect regions 1, 3, and 4 with a new color and not enclose one of them in doing so (thus creating a new "open" color).

However, if we are allowed to wrap then it becomes possible to connect the classes without forming enclosures.

Observe:

5 color with 1 dimension of wrapping:
          |      3
          |
---+      +---+------
 5 |    1 | 2 |  5   ->
---+      +---+------
          |
          |      4


6 color with 2 dimensions of wrapping:
   A    A
   | |  |   |
   6 |  1   |
     +------+      3
            |
  +--+---+  +---+------
<- 5 |   |  |   |  5   ->
  ---+   +--+ 2 |  +---
   6 |      |   |  | 6 ->
     |      +---+--+---
     |  1   |
     |      |      4
   |    |
   v    v


Note that 3 and 4 share a boarder someplace around the wrap.

Is that clear? It's getting complicated enough that the notation is a little odd. I'm pretty sure I didn't cheat...

I don't /think/ you can get more than 5 colors with the tube, or 6 colors on the surface of a sphere.

[identity profile] clockwise.livejournal.com 2006-06-05 07:43 pm (UTC)(link)
hmm, actually my 5 color 1 dim wrapping doesn't work since 3 & 4 are no longer adjacent. Oh well, it was a nice thought.